I'm going to use $I_C$ to denote the current of the current source and $V_V$ to denote the voltage of voltage source. Let's motivate the general proof with a specific example first. Here I prove that the superposition theorem in circuit analysis holds if you restrict to certain elements. Because one describes the linearity of the input/output relationship of the circuit while the other talks about how to solve the circuit by turning off sources. I think that is not correct and actually a bit circular. Ques.It is generally said that the superposition theorem is a result that the circuit is linear. The total voltage (V T) = V 1 + V 2 + V 3 + V 4 Thus, by applying the superposition theorem, Very less amount of current flow is detected through a 15Ω resistor because the circuit has a low resistance path. Here, we will use the current division rule as 40Ω and 15Ω resistors are parallel to each other. The voltage through the 15Ω resistor is : Resultant voltage V 4 = V 1 + V 2+ V 3+ V 4īy considering the 20v source separately, the voltage source is short-circuited and the other two sources are open-circuited.īy applying Kirchhoff's voltage law (KVL), the current flowing through a 15Ω resistor is : The different sources = 20v, 10v, 10A, 5A Overall, the superposition theorem is a powerful tool for simplifying complex circuits and for understanding the behavior of linear circuits with multiple sources.Īns: Let the voltage across 15Ω resistor = V 1, V 2, V 3, V 4.The superposition theorem can also be used to analyze circuits with dependent sources, such as transistors or operational amplifiers. In non-linear circuits, the response due to each source cannot be simply added together. It is important to note that the superposition theorem only applies to linear circuits.This process is repeated for each source.
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |